Angles A and D at the base of trapezoid ABCD are 75 ° and 55 °. Find the degree measures of the rest of its angles.

By the property of a trapezoid, the sum of the angles at the lateral sides of the trapezoid is 180.

Then the angle ABC + BAD = 180.

ABC = 180 – BAD = 180 – 75 = 105.

Angle ВСD + АDC = 180.

BCD = 180 – ADC = 180 – 55 = 125.

Answer: Angle ABC = 180, angle BCD = 125.



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