Aniline was obtained during the reduction of 147.6 nitrobenzene. Calculate the mass of aniline.

1. Let’s compose an equation reflecting the process of nitrobenzene reduction:

C6H5NO2 + 3H2 → C6H5NH2 + 2H2O;

2. Let’s calculate the chemical amount of reduced nitrobenzene:

n (C6H5NO2) = m (C6H5NO2): M (C6H5NO2);

M (C6H5NO2) = 6 * 12 + 5 + 14 + 2 * 16 = 123 g / mol;

n (C6H5NO2) = 147.6: 123 = 1.2 mol;

3. According to the reaction equation, the amounts of nitrobenzene and aniline are the same:

n (C6H5NH2) = n (C6H5NO2) = 1.2 mol;

4. Calculate the mass of aniline:

m (C6H5NH2) = n (C6H5NH2) * M (C6H5NH2);

M (C6H5NH2) = 6 * 12 + 5 +14 + 2 = 93 g / mol;

m (C6H5NH2) = 1.2 * 93 = 111.6 g.

Answer: 111.6 g.