1. Let’s compose an equation reflecting the process of nitrobenzene reduction:
C6H5NO2 + 3H2 → C6H5NH2 + 2H2O;
2. Let’s calculate the chemical amount of reduced nitrobenzene:
n (C6H5NO2) = m (C6H5NO2): M (C6H5NO2);
M (C6H5NO2) = 6 * 12 + 5 + 14 + 2 * 16 = 123 g / mol;
n (C6H5NO2) = 147.6: 123 = 1.2 mol;
3. According to the reaction equation, the amounts of nitrobenzene and aniline are the same:
n (C6H5NH2) = n (C6H5NO2) = 1.2 mol;
4. Calculate the mass of aniline:
m (C6H5NH2) = n (C6H5NH2) * M (C6H5NH2);
M (C6H5NH2) = 6 * 12 + 5 +14 + 2 = 93 g / mol;
m (C6H5NH2) = 1.2 * 93 = 111.6 g.
Answer: 111.6 g.
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