AO = OC BO = OE it is required to prove that AB is parallel to EC.
| March 5, 2021 | education
In triangles AOB and COD, the angle AOB = COD as the vertical angles at the intersection of the segments AC and BD.
By condition, AO = OC, BO = OD, then the triangles AOB and COD are equal on both sides and the angle between them.
Angle ABO = CDO as similar angles of similar triangles, and since these are criss-crossing angles at the intersection of lines AB and DE of the secant BD, and then AB is parallel to CD and EC, which was required to be proved.
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