# Applying a force directed at an angle of 30 degrees to the horizon, a person pulls a sled weighing 40 kg.

**Applying a force directed at an angle of 30 degrees to the horizon, a person pulls a sled weighing 40 kg. At the same time, the sleds move evenly along the horizontal surface. Determine the modulus of the acting force if the coefficient of friction of the sled on the snow is 0.1**

Data: α (angle between the vector of displacement of the sled and the vector of force) = 30º; m (sled weight) = 40 kg; uniform movement; μ (coefficient of friction of the sled on the snow) = 0.1.

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

To determine the modulus of the acting force, we use the equality: m * a = 0 = F * cosα – Ftr = F * cosα – μ * (m * g – F * sinα).

F * cosα = μ * (m * g – F * sinα).

F * cos30º = 0.1 * (40 * 10 – F * sin60º).

F * 0.866 = 40 – 0.1F * 0.5.

0.916F = 40.

F = 40 / 0.916 = 43.67 N.