Archimedes’ law. The density of a body is 1.25 times that of water. How many times will the weight

Archimedes’ law. The density of a body is 1.25 times that of water. How many times will the weight of this body be less in water than in air?

ρt / ρw = 1.25.
Р / Рв -?
The weight of the body in the air Pw is equal to the gravity of the body Ft: P = Ft.
Two forces act on a body immersed in water: the force of gravity Ft, directed vertically downward, and the buoyancy force of Archimedes Farkh, directed vertically upward.
Therefore, the body weight in water Pw will be the difference: Pw = Ft – Farch.
The force of gravity is determined by the formula: Ft = m * g, where m is the mass of the body, g is the acceleration of gravity.
We express the mass of the body m by the product of the volume of the body V by the density of the substance from which it is made ρт: m = V * ρт.
Ft = V * ρt * g.
The value of the Archimedes force Farch is expressed by the formula: Farch = ρw * g * V. Where ρw is the density of the liquid and gas in which the body is immersed, g is the acceleration of gravity, V is the volume of the body, which is immersed in a liquid or gas.
Р / Рв = V * ρт * g / (V * ρт * g – V * ρв * g) = V * 1.25 * ρв * g / (V * 1.25 * ρв * g – V * ρв * g ) = 1.25 / (1.25 – 1) = 5.
Answer: body weight in water will be 5 times less than in air: P / Pw = 5.