Are two right triangles similar if they have a common acute angle?

Let there be given two right-angled triangles with a common acute angle ABC and AOK, they have a common angle at point A: <BAC = <OAK, <ABC = <AOK = 90, let us determine whether the triangles are similar.
Find the missing angles, knowing that the sum of the angles of the triangle is 180, we get:
<ACB = 180-90- <BAC.
<AKO = 180-90- <OAK, taking into account that <BAC = <OAK:
<AKO = 180-90- <OAK = <AKO = 180-90- <BAC = <ACB.
In our triangles, all angles are equal, and the sign of similarity is equality of angles, therefore our triangles are similar.
Answer: Triangles are similar.