Area of the rectangle = 90cm 2. Find the perimeter of the rectangle if one of the sides is 2 times larger than the other.

1. A, B, C, D – the vertices of the rectangle. S – area. The side of the BP rectangle is larger
sides AB by 2 times. P is the perimeter.
2. We take as x the length of the AB side, the length of the AD side – 2x.
3. Let’s make an equation, taking into account that the S of the rectangle is 90 centimeters²:
x x 2x = 90;
2x² = 90;
x² = 45;
x = √45 = √9 x 5 = 3√5.
AB = 3√5 centimeters.
AD = AB x 2 = 3√5 x 2 = 6√5 centimeters.
4.P = 2AD +2 AB = 2 x 3√5 + 2 x 6√5 = 6√5 + 12√5 = 18√5 centimeters.
Answer: P is equal to 18√5 centimeters.