The circle is described around an isosceles triangle, since AB = BC, then the height of the BH divides the base of the AC in half as a median. Angle ABC = 2 * ABН = 2 * 25 = 50.
The sum of the inner angles of the triangle is 180, then the angle BAC = BCA = (180 – ABC) / 2 = (180 – 50) / 2 = 65.
Answer: The angles of the triangle are 50, 60, 60.
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