Arrange the coefficients in the reaction using the electronic balance method, indicate the oxidizing agent

Arrange the coefficients in the reaction using the electronic balance method, indicate the oxidizing agent and reducing agent K2CrO7 + H2O + H2S → Cr (OH) 3 ↓ + S + KOH

Let’s write down the reaction equation (probably there is a typo in the condition and there should be K2Cr2O7) K2Cr2O7 + H2O + H2S = Cr (OH) 3 + S + KOH Find the elements that have changed their oxidation states: 2Cr (+6) – (+ 6e) – > 2Cr (+3) (don’t forget to take this into account 2) – oxidizing agent S (-2) – (- 2e) -> S (0) – reducing agent Let’s arrange the coefficients K2Cr2O7 + H2O + 3H2S = 2Cr (OH) 3 + 3S + 2KOH