As a result of an isobaric process, a monoatomic ideal gas performed work of 900 J

As a result of an isobaric process, a monoatomic ideal gas performed work of 900 J. Determine the change in its internal energy and the amount of heat imparted to the gas.

Given: A (work of an ideal gas as a result of the isobaric process) = 900 J.

Reference values: i (the number of degrees of freedom of molecules of a monatomic gas) = 3.

1) Determine the change in internal energy: ΔU = 0.5 * i * P * ΔV = 0.5 * i * A = 0.5 * 3 * 900 = 1350 J.

2) The amount of heat imparted to the gas during the isobaric process: Q = ΔU + A = 1350 + 900 = 2250 J = 2.25 kJ.

Answer: The change in internal energy is 1350 J; 2.25 kJ of heat was reported to the gas.