As a result of crossing two varieties of the night beauty, 52 plants with pink flowers and 49 with

As a result of crossing two varieties of the night beauty, 52 plants with pink flowers and 49 with white flowers were obtained. Determine the genotypes and phenotypes of the parents?

The actual cleavage obtained in the progeny of the nocturnal belladonna corresponds to a 1: 1 ratio, which usually characterizes the analyzing cross, in which the heterozygote is crossed with the homozygote for a recessive trait.

Suppose the pink color of the flowers of the night beauty dominates over the white one (it should be noted that, taking into account the splitting, in this problem, the specific color taken as the dominant color is not decisive, the white color of the corollas can be conventionally taken as dominant). Let’s designate the gene that causes the flowers of the night beauty to be colored red as K, then the gene for white flowers of this plant will be designated as k.

A plant homozygous for a recessive gene has white flowers and a kk genotype, because this trait can only be phenotypically realized if the genotype is homozygous. This plant is capable of producing germ cells of one type – k.

Heterozygous Night Beauty – Kk. It has pink flowers. The germ cells produced by such a plant are K and k.

The offspring will theoretically be represented by options:

plants with pink flowers (Kk) – 50%;

plants homozygous for the recessive gene, with white flowers (kk) – 50%.

Theoretically, the obtained percentage corresponds to the proportional ratio from the condition of the problem, which confirms the assumption about the analyzing crossing.

Answer: A heterozygous night beauty with pink flowers (Kk) and a night beauty with white flowers homozygous for the recessive gene (kk) were crossed.