As a result of electrolysis of an aqueous solution of potassium chloride, chlorine chemical was released.

As a result of electrolysis of an aqueous solution of potassium chloride, chlorine chemical was released. amount of 0.200 mol and potassium hydroxide was formed. the mass of the solution by the end of the electrolysis was 155 g. Determine the mass fraction of potassium hydroxide in the resulting solution.

2KCl + 2H2O = 2KOH + Cl2
According to the stoichiometry of the reaction:
n (KOH) = 2n (Cl2) = 2 * 0.2 = 0.4 mol;
Find the mass of potassium hydroxide:
m (KOH) = n (KOH) * M (KOH) = 0.4 * 56 = 22.4 g;
Find the mass fraction of potassium hydroxide:
w (KOH) = m (KOH) / m (solution) = 22.4 / 155 = 0.1445 = 14.45%.
Answer: w (KOH) = 14.45%.



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