As a result of friction, 6.4 * 10 ^ (10) electrons were removed from the surface of the glass rod.

| September 2, 2021 | education

As a result of friction, 6.4 * 10 ^ (10) electrons were removed from the surface of the glass rod. Determine the electrical charge on the stick. How much has the stick mass decreased? The mass of an electron is 9.1 * 10 ^ (- 31) kg.

Data: n (number of electrons removed from the rod) = 6.4 * 10 ^ 10 electrons.

Constants: qe (electron charge) = -1.6 * 10 ^ -19 C; by the condition me (electron mass) = 9.1 * 10 ^ -31 kg.

1) The charge of the glass rod under consideration (we assume that before friction the charge of the rod was 0 C): q = -n * qe = 6.4 * 10 ^ 10 * 1.6 * 10 ^ -19 = 10.24 * 10 ^ -9 C = 10.24 nC.

2) Reducing the mass of the stick: Δm = n * me = 6.4 * 10 ^ 10 * 9.1 * 10 ^ -31 = 58.24 * 10 ^ -21 kg = 58.24 zkg.

Answer: The charge of the stick became equal to 10.24 nC; weight decreased by 58.24 kg.



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