As a result of gas combustion, its volume decreased from 8 to 5 liters. and the pressure increased by 60 kPa

As a result of gas combustion, its volume decreased from 8 to 5 liters. and the pressure increased by 60 kPa find the initial volume.

V1 = 8 l = 0.008 m3.

V2 = 5 l = 0.005 m3.

ΔP = 60 kPa = 60,000 Pa.

P1 -?

For constant gas mass, the combined gas law is valid: P1 * V1 / T1 = P2 * V2 / T2.

Gas compression will be considered isothermal, that is, such that its temperature does not change.

For an isothermal process, the Boyle-Mariotte law is valid: P1 * V1 = P2 * V2, according to which the product of the gas pressure and its volume remains unchanged.

P1 = P2 * V2 / V1.

P2 = P1 + ΔP.

P1 = (P1 + ΔP) * V2 / V1.

P1 = P1 * V2 / V1 + ΔP * V2 / V1.

P1 – P1 * V2 / V1 = ΔP * V2 / V1.

P1 * (1 – V2 / V1) = ΔP * V2 / V1.

P1 = ΔP * V2 / V1 * (1 – V2 / V1).

P1 = 60,000 Pa * 0.005 m3 / 0.008 m3 * (1 – 0.005 m3 / 0.008 m3) = 100000 Pa.

Answer: the initial gas pressure was P1 = 100000 Pa.