As a result of intermolecular dehydration of 192 g of methanol in 60% yield, ether was obtained

As a result of intermolecular dehydration of 192 g of methanol in 60% yield, ether was obtained, the mass of which was Determine the mass of this ether.

Given:
m (CH3OH) = 192 g
η (ether) = 60%

To find:
m pract. (ether) -?

Decision:
1) 2CH3OH => (CH3) 2O + H2O;
2) n (CH3OH) = m (CH3OH) / M (CH3OH) = 192/32 = 6 mol;
3) n theory. ((CH3) 2O) = n (CH3OH) / 2 = 6/2 = 3 mol;
4) n practical ((CH3) 2O) = η ((CH3) 2O) * n theory. ((CH3) 2O) / 100% = 60% * 3/100% = 1.8 mol;
5) m practical. ((CH3) 2O) = n practical. ((CH3) 2O) * M ((CH3) 2O) = 1.8 * 46 = 82.8 g.

Answer: The mass of (CH3) 2O is 82.8 g.