As a result of the engine operation, the momentum of the car increased by 2 times.

As a result of the engine operation, the momentum of the car increased by 2 times. How did the kinetic energy of the car change?

Let p1 – the initial momentum of the car, p2 – the final momentum of the car, V1 – the initial speed of the car, V2 – the final speed of the car, m – the mass of the car, E1 – the initial kinetic energy of the car, E2 – the final kinetic energy of the car. p1 = m * V1, p2 = m * V2, by the condition of the problem p2 / p1 = 2, then (m * V2) / (m * V1) = 2, reducing the mass of the car, we get that V2 / V1 = 2. Find , which is equal to E2 / E1 = ((m * V2 ^ 2) / 2) / ((m * V1 ^ 2) / 2), we cancel two and the mass of the car and we get that E2 / E1 = V2 ^ 2 / V1 ^ 2, we have obtained that V2 / V1 = 2, and therefore V2 ^ 2 / V1 ^ 2 = 4, whence it follows that E2 / E1, i.e. the kinetic energy of the car has increased by 4 times.



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