As a result of the interaction of 10.8 g of aluminum with an excess of chlorine

As a result of the interaction of 10.8 g of aluminum with an excess of chlorine, 50 g of AL CL was formed. Determine the yield of the reaction product from the theoretically possible.

Let’s write the reaction equation:
2Al + 3Cl2 = 2AlCl3

Let’s find the theoretical mass of aluminum chloride:
n (Al) = m (Al) / Mr (Al) = 10.8 / 27 = 0.4 mol;

n (AlCl3) theory = n (Al) = 0.4 mol;

m (AlCl3) theory = n (AlCl3) theory * Mr (AlCl3) = 0.4 * 133.5 = 53.4 g.

Let’s find the yield of the reaction product:
Yield = m (AlCl3) prakich / m (AlCl3) theory * 100% = 50 / 53.4 * 100% = 93.6%