As a result of the interaction of 135 g of hydrochloric acid solution with copper (II) sulfide

As a result of the interaction of 135 g of hydrochloric acid solution with copper (II) sulfide, hydrogen sulfide was formed. Determine its volume.

1. The interaction of hydrochloric acid with copper sulfide reflects the reaction:

2HCl + CuS = CuCl2 + H2S ↑;

2. Let’s calculate the chemical amount of hydrogen chloride:

n (HCl) = m (HCl): M (HCl) = 135: 36.5 = 3.6986 mol;

3. Set the amount of released hydrogen sulfide:

n (H2S) = n (HCl): 2 = 3.6986: 2 = 1.8493 mol;

4. Determine the volume of hydrogen sulfide:

V (H2S) = n (H2S) * Vm = 1.8493 * 22.4 = 41.42 liters.

Answer: 41.42 liters.