As a result of the interaction of 24.6 g of a mixture of zinc and zinc oxide with a sufficient amount

As a result of the interaction of 24.6 g of a mixture of zinc and zinc oxide with a sufficient amount of hydrochloric acid, 2.24 liters of hydrogen were released. Calculate the mass of the salt formed.

Zinc reacts with hydrochloric acid according to the following scheme:

Zn + 2HCl → ZnCl2 + H2;

Based on the coefficients of the hydrogen equation, the same amount will be obtained as taken zinc. This will produce the same amount of zinc chloride.

Let’s determine the molar amount of hydrogen.

N H2 = 2.24 / 22.4 = 0.1 mol;

If 0.1 mol of hydrogen was obtained, then 0.1 mol of zinc reacted with the acid.

Its weight is 0.1 x 65 = 6.5 grams.

The remainder is taken up by zinc oxide. Its weight is 24.6 – 6.5 = 18.1 grams;

The amount of zinc oxide is 18.1 / (65 + 16) = 0.223 mol;

We calculate the weight 0.1 + 0.223 = 0.323 mol of zinc chloride.

M ZnCl2 = 65 + 35.5 x 2 = 136 grams / mol;

m ZnCl2 = 0.323 x 136 = 43.928 grams;