As a result of the interaction of aminoacetic acid weighing 90 g with potassium hydroxide

As a result of the interaction of aminoacetic acid weighing 90 g with potassium hydroxide, 100 g of salt was formed. Calculate the mass fraction of the salt yield.

To solve the problem, let’s compose the reaction equation:
CH2 (NH2) – COOH + KOH = CH2 (NH2) – COOK + H2O – exchange reaction, the potassium salt of aminoacetic acid was obtained;
M (aminoox c-ta) = 75 g / mol;
M (salt a / y to-you) = 113.1 g / mol;
Let’s calculate the number of moles of aminoacetic acid:
Y (a / y to-you) = m / M;
Y = 90/75 = 1.2 mol;
Y (salt a / y to-you) = 1.2 mol, since according to the reaction equation, their number is 1 mol.
Determine the theoretical mass of aminoacetic acid:
m (theoretical) = Y * M = 1.2 * 113.1 = 135.72 g.
We find the mass fraction of the salt yield:
W = m (practical) / m (theoretical) * 100;
W = 100 / 135.72 * 100;
W = 73.68%.
Answer: The mass fraction of the yield of the salt of aminoacetic acid is 73.68%.



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