As a result of the interaction of iron with a solution of copper salt (2), metallic copper with a mass of 64 g

As a result of the interaction of iron with a solution of copper salt (2), metallic copper with a mass of 64 g was released. What is the chemical amount of iron that reacted?

Let’s find the amount of copper substance by the formula:

n = m: M.

M (Cu) = 64 g / mol.

n = 64 g: 64 g / mol = 1 mol.

Let’s compose the reaction equation, find the quantitative ratios of substances.

Fe + CuCl2 = FeCl2 + Cu ↓.

According to the reaction equation, there is 1 mole of iron for 1 mole of copper. The substances are in quantitative ratios of 1: 1.

The amount of iron and copper will be equal.

n (Cu) = n (Fe) = 1 mol.

1 mol Fe – 1 mol Cu,

x mol Fe – 1 mol Cu,

x mol Fe = (1 mol × 1 mol): 1 mol = 1 mol.

Answer: 1 mole.