As a result of the interaction of methane CH4 weighing 8 g with oxygen weighing 32 g, carbon dioxide

| February 11, 2021 | education

As a result of the interaction of methane CH4 weighing 8 g with oxygen weighing 32 g, carbon dioxide was formed with a mass of 22 g. Add up the equation for this reaction. Calculate how much water is formed as a result of the reaction.

Method 1: Based on the law of conservation of mass (the sum of the masses of the initial substances is equal to the sum of the masses of the products) m (CH4) + m (O2) = m (CO2) + m (H2O). 8 + 32 = 22 + x, x = 18 g.
Method 2: The coefficient before water and oxygen is the same, equal to 2. Hence, it is more convenient to calculate the mass of water through oxygen. You can make the proportion 32 (mass of oxygen) / 32 (molecular mass of oxygen) = x (mass of water) / 18 (molecular mass of water). x = 18 g.
Also, you can first find the amount of substance v oxygen: v = 32 (mass of oxygen) / (2 (coefficient before oxygen) * 32 (molecular weight of oxygen)) = 32 / (2 * 32) = 0.5 mol. The amount of substance of water and oxygen will be equal, which means that the mass of water will be equal to 0.5 (amount of substance) * 2 (coefficient) * 18 = 18 g.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.