As a result of the reaction between hydrogen and oxygen, water with a mass of 27 g was released.

As a result of the reaction between hydrogen and oxygen, water with a mass of 27 g was released. Find the volume of the gases that reacted.

Let’s implement the solution:
1. According to the condition of the problem, we compose the equation:
X l. -? X l. -? m = 27 g;
2H2 + O2 = 2H2O – compounds, water is released;
2. Calculations by formulas:
M (H2O) = 18 g / mol;
Y (H2O) = m / M = 27/18 = 1.5 mol;
Y (H2) = 1.5 mol since the amount of substances according to the equation is 2 mol.
3. Proportion:
X mol (O2) – 1.5 mol (H2O);
-1 mol – 2 mol from here, X mol (O2) = 1 * 1.5 / 2 = 0.75 mol.
4. Find the volume of H2, O2:
V (H2) = 1.5 * 22.4 = 33.6 L;
V (O2) = 0.75 * 22.4 = 16.8 l;
Answer: to carry out the process, 33.6 liters of hydrogen will be required, oxygen – 16.8 liters.