As a result of the reaction of burning thermite, 160 kJ of heat was released. How many grams of aluminum

As a result of the reaction of burning thermite, 160 kJ of heat was released. How many grams of aluminum did it react? 8Al + 3Fe3O4 = 4Al2O3 + 9Fe + 800kJ. How many grams of aluminum has reacted?

Given:
Q1 = 160 kJ

Find:
m (Al) -?

1) Write the equation of a chemical reaction:
8Al + 3Fe3O4 => 4Al2O3 + 9Fe + 800 kJ;
2) Calculate the amount of Al substance by composing and solving the proportion:
800 kJ – 8 mol of Al;
160 kJ – x mol of Al;
n (Al) = x = 160 * 8/800 = 1.6 mol;
3) Using the periodic system of D.I.Mendeleev, determine the molar mass of Al:
M (Al) = Ar (Al) = 27 g / mol;
4) Calculate the mass of Al:
m (Al) = n (Al) * M (Al) = 1.6 * 27 = 43.2 g.

Answer: The mass of Al is 43.2 g