As a result of the reaction of ethanol with sodium, 44.8 liters of hydrogen are released. The amount of ethanol is …

univerkov | February 10, 2021 | education

1. The interaction of ethanol with sodium is described by the reaction equation:

2C2H5OH + 2Na → 2C2H5ONa + H2;

2.Calculate the chemical amount of hydrogen:

n (H2) = V (H2): Vm = 44.8: 22.4 = 2 mol;

3. Determine the amount of ethanol:

n (C2H5OH) = n (H2) * 2 = 2 * 2 = 4 mol.

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