As a result of the reaction of sulfuric acid and magnesium, Mg (SO4) is formed with a chemical amount of 6 mol.

As a result of the reaction of sulfuric acid and magnesium, Mg (SO4) is formed with a chemical amount of 6 mol. Calculate the mass of the converted Mg and the chemical amount of H2SO4 reacted.

Let’s execute the solution:
1. Let’s compose the equation according to the condition of the problem:
X g -? Y -? Y = 6 mol;
Mg + H2SO4 = MgSO4 + H2 – OBP, obtained magnesium sulfate;
1 mol 1 mol.
2. Calculations:
M (Mg) = 24.3 g / mol;
M (H2SO4) = 98 g / mol;
M (MgSO4) = 96 g / mol.
3. Y (MgSO4) = 6 mol;
Y (H2SO4) = 6 mol;
Y (Mg) = 6 mol since the amount of these substances according to the equation is 1 mol.
4. Find the masses of the starting materials:
m (Mg) = Y * M = 6 * 24.3 = 145.8 g;
m (H2SO4) = Y * M = 6 * 98 = 588 g.
Answer: to carry out the process, you need magnesium weighing 145.8 g, sulfuric acid – 588 g.