As a result of the reduction of silver oxide with acetaldehyde, 2.7 g of silver were formed.

As a result of the reduction of silver oxide with acetaldehyde, 2.7 g of silver were formed. What mass of aldehyde was oxidized in this case?

Let’s write the equation:
СН3 – СОН + Ag2O = CH3 – COOH + 2Ag – qualitative reaction to aldehyde, is released
silver;
Let’s determine the molecular weights of substances:
M (CH3COH) = 44 g / mol;
M (Ag2O) = 231.6 g / mol;
Let’s calculate the amount of moles of silver oxide, if the mass is known:
Y (Ag2O) = m / M = 2.7 / 231.6 = 0.011 mol;
According to the equation, the amount of moles of acetaldehyde and silver oxide are equal, which means that
Y (CH3COH) = 0.011 mol;
Find the mass of acetaldehyde:
m (CH3COH) = Y * M = 0.011 * 44 = 0.48 g.
Answer: the mass of acetaldehyde is 0.48 g.