According to the condition of the problem, we compose the reaction equation:
6СО2 + 6Н2О = С6Н12О6 + 6О2 – the process of photosynthesis, glucose and oxygen are formed;
Let’s make calculations using the formulas:
M (C6H12O6) = 156 g / mol;
M (O2) = 32 g / mol;
Determine the number of moles of glucose if the mass is known:
Y (C6H12O6) = m / M = 3.6 / 156 = 0.023 mol;
Let’s make the proportion:
0.023 mol (C6H12O6) – X mol (O2);
-1 mol -6 mol from here, X mol (O2) = 0.023 * 6/1 = 0.138 mol;
Let’s calculate the volume of oxygen:
V (O2) = 0.138 * 22.4 = 3.09 l.
Answer: in the process of photosynthesis, oxygen is released in a volume of 3.09 liters.
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