At 11:00 the boat left point A to point B, located 30 km from A. After staying at point B at 2:40, the boat set off back
At 11:00 the boat left point A to point B, located 30 km from A. After staying at point B at 2:40, the boat set off back and returned to point A at 19:00. Determine (in km / h) the speed of the river if it is known that the boat’s own speed is 12 km / h.
The boat returned to point A after 19 – 11 = 8 hours.
Taking into account the parking at point B, the boat was on the way
8 – 2 2/3 = 5 1/3 hours.
Let us assume that the speed of the river is x km / h, then the boat was moving downstream at a speed of (12 + x) km / h, and against the current at a speed of (12 – x) km / h.
Let’s compose an equation according to the condition of the problem:
30 / (12 + x) + 30 / (12 – x) = 5 1/3 = 16/3,
(360 – 30x + 360 + 30x) / (12 – x²) = 16/3,
720 / (144 – x²) = 16/3,
16x² = 2304 – 2160,
16x² = 144,
x² = 9,
x = 3.
Answer: 3 km / h.