At 15 ° C, two liters of gas create a pressure of 2.2 atmospheres. How much the pressure will change when the temperature rises to 40 ° C.
Data: T1 (initial gas temperature) = 15 ºС = 15 + 273 K = 288 K; V (constant gas volume) = 2 l; P1 (initial gas pressure) = 2.2 atm .; T2 (final gas temperature) = 40 ° C = 40 + 273 K = 313 K.
1) Determine the value of the gas pressure after increasing the temperature (isochoric process): P1 / T1 = P2 / T2 and P2 = P1 * T2 / T1 = 2.2 * 313/288 = 2.39 atm.
2) Let’s calculate the change in gas pressure: ΔР = Р2 – Р1 = 2.39 – 2.2 = 0.19 atm or 19 kPa.
Answer: The gas pressure will increase by 0.19 atm (19 kPa).
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