At a constant temperature of 27 degrees and a pressure of 10 ^ 5 Pa, the volume of gas is 1m ^ 3.

At a constant temperature of 27 degrees and a pressure of 10 ^ 5 Pa, the volume of gas is 1m ^ 3. At what temperature this gas will occupy a volume of 2m ^ 3 at the same pressure 10 ^ 5 Pa.

To calculate the temperature at which the gas should be, we will use the proportion (isobaric process): V0 / T0 = V / T and T = V * T0 / V0.

Value of variables: V – final volume (V = 2 m3); T0 (initial temperature) = 300 K (27 ºС); V0 (initial volume) = 1 m3.

Let’s calculate: T = V * T0 / V0 = 2 * 300/1 = 600 K (327 ºС).

Answer: Gas will occupy a volume of 2 m3 at a temperature of 600 K.