At a height of 25 meters, the body was thrown vertically downward with an initial speed of 10 m / s.

At a height of 25 meters, the body was thrown vertically downward with an initial speed of 10 m / s. What is the speed at the end of the fall?

The path is found by the formula
S = V ^ 2-Vo ^ 2 / 2g
Now just substitute the values
25 = V ^ 2-100 / 20
500 = V ^ 2-100
600 = V ^ 2
V = √ (600)
V = 24.49 (m / s)
Answer: V = 24.49 (m / s)



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