# At a pressure of 1.5 * 10 Pa, 1 m ^ 3 of gas contains 2 * 10 ^ 25 molecules.

At a pressure of 1.5 * 10 Pa, 1 m ^ 3 of gas contains 2 * 10 ^ 25 molecules. What is the average kinetic energy of the translational motion of these molecules?

Data: P (constant pressure of the taken gas) = 1.5 * 10 ^ 5 Pa; V (gas volume) = 1 m3; N (number of gas molecules) = 2 * 10 ^ 25 molecules.

To calculate the average kinetic energy of the translational motion of the molecules of the taken gas, we use the formula: P = 2/3 * n * Ek = 2/3 * (N / V) * Ek, whence Ek = 3P * V / (2 * N).

Calculation: Ek = 3 * 1.5 * 10 ^ 5 * 1 / (2 * 2 * 10 ^ 25) = 1.125 * 10 ^ -20 J = 11.25 sJ.

Answer: The average kinetic energy is 11.25 SJ.

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