At a pressure of 10 5 Pa for an air density of 1.29 kg / m3. calculate the root mean square velocity of its molecules.

Data: P (intake air pressure) = 10 ^ 5 Pa.

Constants: according to the condition of the problem, ρ (air density) = 1.29 kg / m3.

To calculate the required average velocity of the molecules of the taken air, we apply the formula: P = 1/3 * ρ * V ^ 2, whence V = √ (3P / ρ).

Let’s calculate: V = √ (3 * 10 ^ 5 / 1.29) = 482.2 m / s.

Answer: Molecules of the taken air have a root mean square velocity of 482.2 m / s.