At a pressure of 250 kPa, a gas weighing 8 kg occupies a volume of 15 m3.

At a pressure of 250 kPa, a gas weighing 8 kg occupies a volume of 15 m3. What is the root-mean-square velocity of gas molecules

Task data: P (gas pressure) = 250 kPa = 250 * 10 ^ 3 Pa; m (gas mass) = 8 kg; V (volume occupied by gas) = 15 m3.

The root-mean-square velocity of gas molecules can be determined from the basic equation of the molecular-kinetic theory of an ideal gas: Р = m * υ ^ 2 / 3V, whence υ = √ (3Р * V / m).

Let’s calculate: υ ^ 2 = √ (3 * 250 * 10 ^ 3 * 15/8) ≈ 1186 m / s.

Answer: The mean square velocity of gas molecules is 1186 m / s.