At a temperature of 23 ° C, the gas pressure in the vessel was 50 kPa, which will be the gas pressure at 123 ° C.

Task data: T1 (initial temperature) = 23 ºС (296 K); P1 (initial pressure) = 50 kPa; Т2 (considered temperature) = 123 ºС (396 К); isochoric process (one and the same vessel).

To calculate the pressure of the taken gas at 123 ºС, we apply the proportion: P1 / T1 = P2 / T2 and P2 = P1 * T2 / T1.

Calculation: P2 = 50 * 396/296 = 66.89 kPa.

Answer: The gas pressure will increase to 66.89 kPa.



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