At a temperature of 294 K, the volume of gas is 0.35 dm ^ 3. At what temperature will the volume of the same mass
| September 1, 2021 | education
At a temperature of 294 K, the volume of gas is 0.35 dm ^ 3. At what temperature will the volume of the same mass of gas increase to 0.4 dm ^ 3? The gas pressure is considered constant.
Task data: T1 (initial temperature) = 294 K; V1 (initial volume) = 0.35 dm3; V2 (required volume) = 0.4 dm3; pressure is constant (isobaric expansion).
To find the desired temperature of a given gas, apply the proportion: V1 / T1 = V2 / T2, whence T2 = V2 * T1 / V1.
Let’s calculate: T2 = 0.4 * 294 / 0.35 = 336 K.
Answer: The volume of the given gas will be equal to 0.4 dm3 at a temperature of 336 K.
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