# At a temperature of 5 degrees Celsius, the air pressure is 10 ^ 4 Pa.

At a temperature of 5 degrees Celsius, the air pressure is 10 ^ 4 Pa. At what temperature the air pressure in it will be 2.6×10 ^ 4 Pa. The volume does not change.

Given:

T1 = 5 ° Celsius = 278 ° Kelvin – initial air temperature;

P1 = 104 Pascal = 10000 Pascal – initial air pressure;

P2 = 2.6 * 104 Pascal = 26000 Pascal – final air pressure;

It is required to determine T2 (Celsius scale) – the final air temperature.

Since, according to the condition of the problem, the volume remains constant, then the final air temperature can be determined from the following ratio:

P1 / T1 = P2 / T2, from here we find:

T2 = P2 * T1 / P1 = 26000 * 278/10000 = 2.6 * 278 = 722.8 ° Kelvin = 449.8 degrees Celsius.

Answer: the air temperature will become equal to 449.8 ° Celsius.

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