At a temperature T 0 and a pressure p 0, one mole of an ideal gas occupies a volume Vq. what is the volume of this same gas

At a temperature T 0 and a pressure p 0, one mole of an ideal gas occupies a volume Vq. what is the volume of this same gas, taken in an amount of 2 mol, at the same pressure p0 and temperature 2 To?

For n moles of an ideal gas, the following expression is valid:
PV = nRT, where R is the universal gas constant.
V = nRT / P.
Volume of 1 mole of ideal gas at T = T₀ and P = P₀:
Vq = (1 mol * RT₀) / P₀ (1).
The volume of two moles of an ideal gas at T = 2T₀ and P = P₀:
V₁ = (2 moles * R * 2T₀) / P₀ (2).
Divide (2) by (1):
V₁ / Vq = 4;
V₁ = 4 * Vq.

Answer: 4 * Vq.