At a voltage of 110 V, which is supplied to the resistor, the current in it is 5 A. What will be the current in the resistor
July 5, 2021 | education
| At a voltage of 110 V, which is supplied to the resistor, the current in it is 5 A. What will be the current in the resistor if the voltage across it is increased by 10 V?
U1 = 110 V.
I1 = 5 A.
U2 = U1 + 10 V.
t = 10 min = 600 s.
I2 -?
According to Ohm’s law for a section of the circuit, the current in the conductor I is directly proportional to the voltage U and inversely proportional to its resistance R: I = U / R.
I2 = U2 / R.
I1 = U1 / R.
Since the resistance of the conductor does not depend on the voltage and is a characteristic of the conductor, then R = U1 / I1.
The formula for the current strength will take the form: I2 = U2 * I1 / U1.
I2 = 120 V * 5 A / 110 V = 5.5 A.
Answer: the current in the second resistor will be I2 = 5.5 A.
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