At a voltage of 110V at the terminals of the resistor, the current is 4A. When the voltage across the resistor

| September 15, 2021 | education

At a voltage of 110V at the terminals of the resistor, the current is 4A. When the voltage across the resistor is increased to 220V, what will be the current strength?

Given:

U1 = 110 Volts – voltage at the terminals of the resistor;

I1 = 4 Amperes – current strength at voltage equal to U1;

U2 = 220 Volts.

It is required to determine I2 (Ampere) – the current strength at a voltage equal to U2.

Let’s find the resistance of the resistor (according to Ohm’s law):

U1 = I1 * R, hence:

R = U1 / I1 = 110/4 = 27.5 ohms.

The resistance of the resistor remains unchanged in any case. Then the current strength at voltage U2 will be equal to:

I2 = U2 / R = 220 / 27.5 = 8 Amps.

Answer: when the voltage increases to 220 volts, the current strength will be 8 amperes.



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