At a voltage of 12 V, the current in the resistor is 0.5 A. When another resistor was connected in series

At a voltage of 12 V, the current in the resistor is 0.5 A. When another resistor was connected in series with it, the current was 0.3 A (at a constant voltage). Find the resistance of the resistors.

Data: U0 (initial voltage) = 12 V (constant value); I0 (initial current in the first resistor) = 0.5 A; serial connection; I (final current in the first resistor) = 0.3 A.

1) Resistance of the first resistor: R1 = U0 / I0 = 12 / 0.5 = 24 Ohm.

2) Total resistance: R = U0 / I = 12 / 0.3 = 40 Ohm.

3) Resistance of the second resistor: R2 = R – R1 = 40 – 24 = 16 Ohm.

Answer: The first resistor has a resistance of 24 ohms; the second resistor is 16 ohms.