At a voltage of 220 V in the electric motor of the washing machine, 396 kJ of energy was consumed within

At a voltage of 220 V in the electric motor of the washing machine, 396 kJ of energy was consumed within 10 minutes. Determine the amperage and amperage in the motor.

Initial data: U (voltage on the washing machine electric motor) = 220 V; t (duration of the washing machine) = 10 minutes (600 s); Q (consumed amount of energy) = 396 kJ (396 * 10 ^ 3 J).

1) Calculate the current power: P = Q / t = 396 * 10 ^ 3/600 = 660 W.

2) Determine the current in the motor: I = P / U = 660/220 = 3 A.

Answer: The current power is 660 W, the current in the washing machine motor is 3 A.