At a voltage of 220 V, the current in the resistor is 6 A. What will the current in it be if the voltage is reduced to 110 V

At a voltage of 220 V, the current in the resistor is 6 A. What will the current in it be if the voltage is reduced to 110 V? If the voltage is reduced by 4 times.

Data: U0 (initial voltage across the resistor) = 220 V; I0 (initial current strength) = 6 A; U1 (first reduced voltage) = 110 V; U2 (second reduced voltage) = U0 / 4.

1) Determine the resistance of the given resistor: R = U0 / I0 = 220/6 = 36.67 Ohm.

2) Current at 110 V: I1 = U1 / R = 110 / 36.67 = 3 A.

3) Current at voltage U0 / 4: I2 = U0 / 4 * R = (220/4) / 36.67 = 1.5 A.