At a voltage of 400 V, the current in the electric motor is 92 A. Determine the power of the current
| April 25, 2021 | education
At a voltage of 400 V, the current in the electric motor is 92 A. Determine the power of the current in the turns of the winding of the electric motor and their resistance.
Initial data: U (voltage on the turns of the electric motor winding) = 400 V; I (current in the electric motor) = 92 A.
1) Let’s calculate the current power on the winding turns: P = U * I = 400 * 92 = 36 800 W = 36.8 kW.
2) Determine the resistance of the turns of the motor winding: R = U / I = 400/92 ≈ 4.35 Ohm.
Answer: The current power on the turns of the electric motor winding is 36.8 kW, and the resistance is 4.35 ohms.
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