At a voltage of 400 V, the current in the motor winding is 92 A. Determine the current power in the motor

At a voltage of 400 V, the current in the motor winding is 92 A. Determine the current power in the motor winding and the amount of heat released in it in 0.25 hours.

Data: U (operating voltage) = 400 V; I (current in the winding of the motor used) = 92 A; t (operating time) = 0.25 h (in SI t = 900 s).

1) Current power in the winding of the electric motor used: P = U * I = 400 * 92 = 36.8 * 10 ^ 3 W (36.8 kW).

2) The amount of heat: Q = U * I * t = P * t = 36.8 * 10 ^ 3 * 900 = 33.12 * 10 ^ 6 J (33.12 MJ).

Answer: The current power is 36.8 kW; in 0.25 h, the used electric motor released 33.12 MJ of heat.