At a voltage of 450V, the current in the electric motor is 90A. Determine the power and resistance in the motor winding.

univerkov | November 27, 2020 | education

Given:
U (voltage) = 450V
I (current) = 90A
To find:
R (resistance) -?
P (power) -?
Decision:
R = U / I; P = U * I
R = 450V / 90A = 5 Ohm
P = 450B * 90A = 40500W = 40.5kW
Answer: 5 ohms; 40.5kW

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