At an altitude of 7134 m, corresponding to Lenin Peak, atmospheric pressure is p = 3.8 * 10⁴ Pa.

At an altitude of 7134 m, corresponding to Lenin Peak, atmospheric pressure is p = 3.8 * 10⁴ Pa. Determine the air density at this height at a temperature of t = 0 degrees C. The molar mass of air is M = 2.9 * 10⁴kg / mol.

As we know from the school physics course, air density can be calculated using the famous Mendeleev-Cliperon formula:

ρ = (p * M) / (R * T).

Let us determine what value the air density will equal at a temperature equal to 0 °, when it is known from the condition of our problem that the pressure is 3.8 * 10 ^ 4 Pascals:

0 ° Celsius is the same as 273 Kelvin;

R is a universal gas constant, it is equal to 8.31 J / (mol * K);

Molar mass of air = 29 * 10-3 kg / mol;

(3.8 * 10 ^ 4 * 29 * 10-3) / (8.31 * 273) ≈ 0.485 kg / m3.

Answer: 0.485 kg / m3.