At constant pressure, the gas heats up from 27 degrees to 52 degrees. The volume increases by 2 liters.

At constant pressure, the gas heats up from 27 degrees to 52 degrees. The volume increases by 2 liters. find the initial volume.

Data: isobaric process; T1 (initial temperature of the taken gas) = 27 ºС (absolute temperature T1 = 300 K); Т2 (final temperature) = 52 ºС (absolute temperature T2 = 325 К); ΔV (volume change) = 2 liters.

To find the initial volume of taken gas, apply the proportion: V1 / T1 = V2 / T2 = (V1 + ΔV1) / T2.

Substitute the given values: V1 / 300 = (V1 + 2) / 325.

V1 * 325 = (V1 + 2) * 300.

325V1 = 300 V1 + 600.

25V1 = 600 and V1 = 600/25 = 24 HP

Answer: The original volume was 24 liters.



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