At noon, a bus left the village for the city. He was driving at a constant speed and would have arrived in the mountains

At noon, a bus left the village for the city. He was driving at a constant speed and would have arrived in the mountains at one o’clock, but on the way he broke down. The driver spent a third of the time spent on the road from the village to the place of breakdown on repairs. To arrive in the city on schedule, the driver had to drive on the remaining section of the road at a speed 2 times higher than planned. What time did the clock show when the bus broke down?

To calculate the breakdown time of the bus in question, we will use the equality: V * t (distance between the village and the city) = V * tp (path to the breakdown site) + 2V * (t – tp – 1/3 tp) = V * tp + nV * (t – 4/3 tp); t = tp + 2 * (t – 4/3 tp).

Variables: t – elapsed time (t = 1 hour).

Let’s perform the calculation: t = tp + 2 * (t – 4/3 tp); 1 = tp + 2 * 1 – 8/3 tp; 8/3 tp – tp = 1 and tp = 1 / (5/3) = 1 * 3/5 = 0.6 h = 36 minutes.

Answer: At the time of the breakdown of the bus in question, the clock showed 12:36.